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9x2+6(n+1)x+n2+5是一個完全平方式,求n的值

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宸茬煡鍏充簬x鐨勪竴鍏冧簩嬈℃柟紼媥虜-(1+2k)x+k虜-2=0鏈変袱涓疄鏁版牴錛屼竴嬈″嚱鏁

有兩個實數(shù)根。△=(2k+1)2-4(k2-2)>=0 4k2+4k+1-4k2+8>=0 4k>=-9 k>=-9/4 y=kx+1遞減,K<0 所以-2.25=1. 計算 (1)(2a^2 b^2c)^4z÷(-2ab^2c^2)^2 (2) (3x^3y^3z)^4÷(3x^3y^2 z)^2÷(2分之1x^2y^61. 計算 (1)(2a^2 b^2c)^4z÷(-2ab^2c^2)^2 =2^4a^8 b^8c^4z÷2^2a^2b^4c^4 =2^2a^6b^4z =4a^6b^4z (2) (3x^3y^3z)^4÷(3x^3y^2 z)^2÷(2分之1x^2y^6 z) = 3^4x^12y^12z^4÷(3^2x^6y^4z^2÷(2分之1x^2y^6 z) = 9x^6y^8z^2÷(2分之1x^2y^6 z) =18x^4y^2z (3) 3a^2x^3÷(3分之1ax)·(-4a^5x^3)÷(6a^2 x^5) =9ax^2·*(-4a^5x^3)÷(6a^2 x^5) =-36a^6

找規(guī)律:2x^2,-3x^3,5x^4,-9x^5,17x^6,-33x^7……第n個數(shù)是__第8個數(shù)是__

第n個數(shù)是

第8個數(shù)是

3ax2-6(2a+1)x+12因式分解?

3ax^2-6(2a+1)x+12 因式分解后 =(3ax-6)(x-2)
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