約分2bc/ac等于多少

2bc/ac =2b/a(x+y)y/xy^2=(x+y)/xyx^2+xy/(x+y)^2= x/(x+y)x^2-y^2/(x-y)^2=(x+y)/(x-y)2c/bd與3ac/4b^2 8bdc/4b^2d 3ac^2/4b^22xy/(x+y)^2與x/x^2-y^22xy(x-y)/(x+y)^2(x-y)與x(x+y)/(x^2-y^2)(x+y)

求數(shù)學(xué)學(xué)霸解決！第一題約分，寫在紙上拍給我就好，急?。。?！

初2數(shù)學(xué)題約分。。。?？禳c(diǎn)。。

2b/a (x+y)/xy x/(x+y) (x+y)/(x-y) 1/5x (3b+2c)/a 3a+b (x-6)/2

初三數(shù)學(xué)

(1)2bc/ac同時(shí)約掉c,則是2b/a (2)(x+y)y/xy^2同時(shí)約掉y,則是(x+y)/xy (3) x^2+xy/(x+y)^2可以同時(shí)約掉( x+y),則是(x+1)/(x+y) (4) x^2-y^2/(x-y)^2同時(shí)約掉(x+y)/(x-y) 通分： (1)2c/bd與3ac/4b^2,分母為4db*b, 分子為8bc+12acd (2) 2xy/(x+y)^2與x/x^2-y^2,分母為(x-y)*(x+y)^2 分子為2xy(x-y)+x(x+y) 做這種題目只要找分母的公約式和最小公倍式就可以了,沒那么難的 都初三了還問這種題目，你得加油學(xué)習(xí)啊 **********

初二數(shù)學(xué)約分??！今晚要??！高手快進(jìn)?。。。。】杉臃郑。。?！

1、2bc / ac= 2b/a 2、(x+y) / xy^2= (x+y) / xy^2 3、x^2+xy / (x+y)^2=x(x+y)/ (x+y)^2=x/x+y 4、x^2-y^2 / (x-y)^2=(x+y)(x-y)/(x-y)^2=(x+y)/(x-y) 5、9a^2+6ab+b^2 / 3a+b=(3a+b)^2/3a+b=3a+b 6、x^2-36 / 2x+12=(x+6)*(x-6)/2(x+6)=(x-6)/2